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moores law and time estimates

moores-cracking.c

if cracking time estimates are higher than the length of time you'd go without upgrading your computer..

you can reduce the estimation based on how many times you think you'd upgrade your computer.

year 0: 100 years left

year 2: 98/2=49 years left

year 4: 47/2=~24 years left

year 6: ~22/2=~11 years left

year 8: ~9/2=~5 years left

year 10: ~3/2=~2 years left

year 12: ~0 years left

let u be time between upgrades

let f be the relative increase in speed between upgrades...

let t be initial time

years_left=100;

for(year=1 ; year < years_left ; year++ , years_left--) {

if(year % u == 0) years_left /= 2;

}

printf("years taken: %d",year);