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stack-based and lightweight programming language.
it uses the postfix notation.
this book has a great pace and nice illustrations
pForth - portable Forth in 'C'
Introduction to Thoughtful Programming and the Forth Philosophy By Michael Misamore
forth editor lifted from easy forth - by eli_oat
these are some words for doing arithmetic with paces (min/km) and velocities (km/hr) relevant to running.
( running.forth ) : minseg>seg swap 60 * + ; ( min segs -- segs ) : seg>minseg 60 /mod swap ; ( segs -- min segs ) : horminseg>seg minseg>seg swap 3600 * + ; ( hr min segs -- segs ) : minseg/m>seg/1km >r minseg>seg 1000 swap r> */ ; ( min segs metros -- segs1km ) : seg/1km>vel 3600 swap / ; ( segs1km -- vel ) : paso>vel minseg>seg seg/1km>vel ; ( min segs -- vel ) : vel>seg/1km 3600 swap / ; ( vel -- segs1km ) : minseg- minseg>seg >r minseg>seg r> - seg>minseg ; ( min segs min segs -- min seg ) ( print ) : .min 0 <# [CHAR] ' HOLD #S #> TYPE ; ( min -- ) : .segpad 0 <# [CHAR] " HOLD # # #> TYPE ; ( segs -- ) : .seg 0 <# [CHAR] " HOLD #S #> TYPE ; ( segs -- ) : .minseg 60 /mod dup 0> IF .min .segpad ELSE drop .seg THEN ; ( segs -- ) : .vel . ." km/hr " ; : lista-velocidades cr 21 10 do i dup .vel vel>s1k .ms cr loop ;
in order to load them, you'd do:
include running.forth
for example, to convert a velocity to a pace, and print it:
18 vel>seg/1k .minseg output: 3'20" ok
to do the opposite operation:
3 20 paso>vel .vel output: 18 km/hr ok
to get the pace of a given segment, using minutes, seconds and distance in meters:
( 1'03" in 300m ) 1 03 300 minseg/m>seg/1k .minseg output: 3'30" ok
to get the difference between two times in minutes, seconds:
( 3'20" - 3'15" ) 3 20 3 15 minseg- minseg>seg .minseg output: 5" ok
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