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⬅️ Previous capture (2022-04-28)
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a quick and dirty turing machine simulator, written in C89.
#include <stdio.h> #define TAPE_SIZE 80 #define RULES_SIZE 256 typedef struct { char state; /* current state */ char symbol; /* current symbol */ int head; /* index of head */ char tape[TAPE_SIZE]; /* tape of characters */ int nrules; /* number of rules */ /* state, symbol, new state, new symbol, direction (even right, odd left ) */ char rules[RULES_SIZE][5]; } Machine; Machine m; int nsteps; int main(int argc, char *argv[]){ int i,n=0; FILE *f; if(!(f = fopen(argv[1], "r"))){ fprintf(stderr, "failed to load file\n"); return 1; } printf("%s\n\n", argv[1]); /* read machine description */ printf("initial state: "); fscanf(f,"%c",&m.state); printf("%c\n",m.state); printf("initial tape: "); fscanf(f,"%s",m.tape); printf("%s\n",m.tape); printf("initial position of head: "); fscanf(f,"%d",&m.head); m.head = (m.head+TAPE_SIZE)%TAPE_SIZE; printf("%d\n",m.head); printf("number of rules: "); fscanf(f,"%d",&m.nrules); printf("%d\n",m.nrules); for(i=0; i<m.nrules; i++){ printf("rule number %d: ",i); fscanf(f,"%s",m.rules[i]); printf("%s\n",m.rules[i]); } printf("max number of simulation steps: "); fscanf(f,"%d",&nsteps); printf("%d\n\n",nsteps); /* simulate */ int irules; /* rules index */ do{ printf("step %d\n",n); /* print head and state */ for(i=0; i<m.head; i++) printf(" "); printf("%c\n",m.state); /* print tape: */ printf("%s\n",m.tape); /* get symbol at head position */ m.symbol = m.tape[ m.head ]; /* search for corresponding rule */ irules = -1; for(i=0; i<m.nrules && irules<0; i++) if(m.rules[i][0] == m.state && m.rules[i][1] == m.symbol) irules = i; if( irules == -1) /* halt if not found */ printf("halted\n"); else{ /* update machine otherwise */ m.state = m.rules[irules][2]; /* new state */ m.tape[ m.head ] = m.rules[irules][3]; /* new symbol */ /* move head */ if( m.rules[irules][4]%2 ) /* if odd, move to left */ m.head = (m.head-1+TAPE_SIZE)%TAPE_SIZE; else /* if even, move to right */ m.head = (m.head+1)%TAPE_SIZE; } printf("\n"); }while( ++n<nsteps && irules != -1); return 0; }
to build:
cc -std=c89 -Wall turingsim.c -o turingsim
to run with an input file:
./turingsim parentesis.txt | less
the line-based fields are:
this input file corresponds to the "comprobador de paréntesis" machine described in máquinas de turing
a A(()())A 1 11 a)bX1 a(a(0 aAcA1 aXaX0 b)b)1 b(aX0 bAH00 bXbX1 c(H00 cAH10 cXcX1 80
the output for this example file looks as follows:
parentesis.txt initial state: a initial tape: A(()())A initial position of head: 1 number of rules: 11 rule number 0: a)bX1 rule number 1: a(a(0 rule number 2: aAcA1 rule number 3: aXaX0 rule number 4: b)b)1 rule number 5: b(aX0 rule number 6: bAH00 rule number 7: bXbX1 rule number 8: c(H00 rule number 9: cAH10 rule number 10: cXcX1 max number of simulation steps: 80 step 0 a A(()())A step 1 a A(()())A step 2 a A(()())A step 3 b A((X())A step 4 a A(XX())A step 5 a A(XX())A step 6 a A(XX())A step 7 b A(XX(X)A step 8 a A(XXXX)A step 9 a A(XXXX)A step 10 b A(XXXXXA step 11 b A(XXXXXA step 12 b A(XXXXXA step 13 b A(XXXXXA step 14 b A(XXXXXA step 15 a AXXXXXXA step 16 a AXXXXXXA step 17 a AXXXXXXA step 18 a AXXXXXXA step 19 a AXXXXXXA step 20 a AXXXXXXA step 21 c AXXXXXXA step 22 c AXXXXXXA step 23 c AXXXXXXA step 24 c AXXXXXXA step 25 c AXXXXXXA step 26 c AXXXXXXA step 27 c AXXXXXXA step 28 H 1XXXXXXA halted
the 1 written at the end indicates that the parenthesis sequence was well-formed. if there was a parenthesis without its pair, the machine would have written 0 instead.
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