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And we're off!
I wonder if I got a bit too clever by half in this solution, as I've been looking over older solutions and can't even remember solving them. But that's how it goes I guess.
Puzzle rating: 3/5
Score: 2
A "standard" Perlish solution (well, *my* kind of Perl, anyway): a dispatch table for the else/if "switch" construct, and a compact hash containing the state of the two solutions.
Puzzle rating: 3/5
Score: 2
I was honestly surprised that the canonical solution to this wasn't some esoteric bit-twiddling trick that reduces it to a one-liner.
In part 2, the naive solution is to loop through each "column" to determine which values to count so as to determine whether they are most frequent or not. I used an index for each "set" to keep track of the values already assigned to that set.
Puzzle rating: 3/5
Score: 2
Fairly straight-forward, although part 2 threw me for a loop. I didn't find a good way to determine the exit condition.
Puzzle rating: 4/5
Score: 2
Finally ok with my solution.
The first attempt got the job done, but was super-scruffy. I realized after I'd finished that I could treat the direction as unit vectors and work from there, so I re-wrote my solution, but only in as so far as to use the direction as a "selector" to chose which subroutine to call to "paint" the map.
After adding that to the repo, I finally remembered what I'd decided before the rewrite - to use the value of the vector in the paint routine itself.
Note that just using `atan2` blindly to determine the direction will point the Y axis incorrectly. It's probably only an issue if you're printing the results, but I found that very helpful in debugging.
If anything good can be said about this method is that I eliminated a lot of weirdness along the way. It wasn't all wasted effort.
Puzzle rating: 3/5
Score: 2
I got off on a bad start with this puzzle, because it worked perfectly for the test input but failed for my puzzle input. I whinged about it on IRC, mentioning I had a very old fish (41 days!). Turns out that was a mispaste and fixing that gave me the correct solution.
I got the answer to the second part 40 seconds later.
Puzzle rating: 4/5, just because my solution was so smooooth
Score: 2
A quite fun one, and the first this year I managed to solve within 1hr of release. This might be TMI but I usually perform my morning ablutions and brew a pot of coffee before starting on a puzzle.
Thinking about this led me to try the average (mean) of the values as the natural solution, but that gave incorrect values. So I just checked the fuel consumption for each and every possible end point, selecting the minimum value. This went plenty fast, as did part 2 once I didn't actually step through each distance calculating fuel as I went (hint: google "Gauss sum 100").
When I had both solutions, I checked the various IRC chats and subreddits and discovered a raging debate on whether taking the median for part 1 and the average for part 2 always gave the correct result for every input. For me they did, so I just restricted by search space to the span of these values, plus a few extra integers for safety. This shaved a couple more milliseconds off the run time.
Puzzle rating: 4/5, I like grade school math
Score: 2
Today was a tough one - not the problem, per se, but commitments that made it hard to me to get to a solution that I was happy with.
In the end I just went for brute-forcing every possible permutation, which is 7! or 5,040. The solution takes around 2s to run on my VPS.
Puzzle rating: 3/5, bit fiddly
Score: 2
This was a straight-forward problem.
I'm a bit surprised my BFS solution worked first time.
Puzzle rating: 3/5
Score: 2
Not the most elegant solution but it gets the job done.
Puzzle rating: 3/5
Score: 2
Nice and easy, got 2 stars within one hour of downloading the input.
I don't think my handling of some flags (`$has_changed`, `$has_synced`) is the most elegant. I'm pretty sure I'm doing an extra scan of the entire map every step to ensure everything has settled down. But I get a result within 1s (*just*) so let's do some weekend chores instead.
I suspect tomorrow will be... more challenging.
Puzzle rating: 3/5
Score: 2
I had to look up a solution for this, which was kind of embarrasing for such an early problem.
Full credit in source.
Puzzle rating: 3/5
Score: __0__
As usual, a breather after the weekend.
I was tearing my hair out, running spot checks on my code, before I realized I had coded my output incorrectly.
The rest of my issues was making it read the right way up...
"Best" result so far, around rank 6,500 for part 1...
Puzzle rating: 3/5
Score: 2
A tough but fun problem.
Part 1 only for now.
Puzzle rating: 4/5
Score: 2
I think I finally figured out <strike>A\*</strike>Dijkstra's. With the help of a lot of cribbing from previous solutions (like 2018 day 22).
I've only included part 2 because I can't be bothered bounding the box for part 1 so it doesn't choose a cheaper solution outside those limits.
Puzzle rating: 4/5
Score: 2
Many people went "BERR" when they saw this: Binary Encoded Register Rodeo!
I had a lot of problems with this, mostly because I managed to get the correct solution for part one a bit by accident, which didn't help solving part 2.
After a day of tearing my hair trying to pass data between recursion levels I managed to solve it.
Puzzle rating: 4/5 - tough, but fair
Score: 2
Suspiciously easy.
This year's last weekend is coming up.
Brace yourselves.
Puzzle rating: 3/5
Score: 2
Actually less complicated then at first glance. The main issue was figuring out how to implement the rules where "explode" had higher precedence than "split", but I managed that with a stack.
Puzzle rating: 4/5
Score: 2
A fun problem. I found a list of all possible rotation transforms and used them to generate the set of rotations to try, then just compared each and every one to find offsets. Runtime is around 15s.
Puzzle rating: 4/5
Score: 2
Back on track after a tough weekend - which I had to skip due to travel.
This was a fun problem once you figured out the trick.
Puzzle rating: 4/5
Score: 2
A fun problem, but part 2 was too tough for me. I copped out and took a "free" star. Full credit in source!
Puzzle rating: 4/5
Score: __1__
Cubes - IN SPACE!!
I only had time for part 1 on release day.
Part 2 completed on 2021-01-04.
Puzzle rating: 4/5
Score: 2
A fun problem but one I had to skip on release day due to preparations for Christmas.
We've seen this sort of thing before, I solved it using Dijkstra's.
In general, we have a start state and an end state, and we can generate new states based on the given rules. These intermediate states can be seen as nodes in a graph we're constructing on the fly. Applying the movement costs for each amphipod gives the total cost for moving form start to end, and Dijkstra's algorithm gives the lowest cost.
Puzzle rating: 4/5
Score: 2
I had to crib a solution (credit in source, of course) but I gave myself a point because it was Christmas Eve and that's when we get presents here, damnit.
Puzzle rating: 4/5
Score: __1__
And... it's a wrap.
Not the most elegant solution but it's a star. I'll take it.
Puzzle rating: 3/5
Score: 2 (assuming I fix the missing stars!)
[Related to this entry](https://gerikson.com/blog/comp/adventofcode/Howto-AoC.html).
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