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And we're off!
I wonder if I got a bit too clever by half in this solution, as I've been looking over older solutions and can't even remember solving them. But that's how it goes I guess.
Puzzle rating: 3/5
Score: 2
A "standard" Perlish solution (well, *my* kind of Perl, anyway): a dispatch table for the else/if "switch" construct, and a compact hash containing the state of the two solutions.
Puzzle rating: 3/5
Score: 2
I was honestly surprised that the canonical solution to this wasn't some esoteric bit-twiddling trick that reduces it to a one-liner.
In part 2, the naive solution is to loop through each "column" to determine which values to count so as to determine whether they are most frequent or not. I used an index for each "set" to keep track of the values already assigned to that set.
Puzzle rating: 3/5
Score: 2
Fairly straight-forward, although part 2 threw me for a loop. I didn't find a good way to determine the exit condition.
Puzzle rating: 4/5
Score: 2
Finally ok with my solution.
The first attempt got the job done, but was super-scruffy. I realized after I'd finished that I could treat the direction as unit vectors and work from there, so I re-wrote my solution, but only in as so far as to use the direction as a "selector" to chose which subroutine to call to "paint" the map.
After adding that to the repo, I finally remembered what I'd decided before the rewrite - to use the value of the vector in the paint routine itself.
Note that just using `atan2` blindly to determine the direction will point the Y axis incorrectly. It's probably only an issue if you're printing the results, but I found that very helpful in debugging.
If anything good can be said about this method is that I eliminated a lot of weirdness along the way. It wasn't all wasted effort.
Puzzle rating: 3/5
Score: 2
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Updated on Sunday, 2021-12-05
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