Comment by Wyboth on 03/10/2014 at 14:50 UTC

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View submission: /r/xkcd is free?

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I think it was this,[1] but I'm not sure.

1: http://www.reddit.com/r/anonymous123421/comments/1w8aie/petition_to_reinstate_uwyboth_as_a_mod_of_rxkcd/cezp63m?context=3

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There's nothing here!