Comment by Wyboth on 09/08/2014 at 12:36 UTC

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View submission: /r/xkcd is free?

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Nope, that's it. I *think* /u/Flytape was trying to say "that's what good meta-subs do, shame on you, /r/conspiratard," but you can never really be sure with him.

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There's nothing here!