I was wondering: if we roll opposed 2d6 rolls, what are the chances of beating your opponent? It must be around 50% but somewhat less, because both rolling a seven – the most likely result – is undecided, that is: you didn’t beat your opponent.
And what about your chances when you get a +1 and your opponent doesn’t? I started wondering but I also didn’t want to dive back into the introduction to statistics I must have in my bookshelf somewhere. And I also didn’t want to look it up on AnyDice.
I started thinking: with just 2d6, it should be possible to explain it all using tables and counting... and I did it! I wrote a little three page PDF about it: Understanding 2d6 Math.
Enjoy! 🙂
#RPG #Indie #2d6 #Just Halberds
(Please contact me if you want to remove your comment.)
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I’d also consider `loop N over {0..11}{output 2d6-2d6<N named "+[N]"}`
– edkalrio 2020-04-23 12:19 UTC
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Oh, very cool! Thank’s a lot.
– Alex Schroeder 2020-04-23 18:07 UTC
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Ynas Midgard’s review of Best Left Buried makes me think I should have a look at its mechanics...
Ynas Midgard’s review of Best Left Buried
– Alex Schroeder 2020-04-27 08:17 UTC
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It always struck me as super weird that Starblazer and Anglerre didn’t use 2d6 vs 7 instead of the cockamamie system it went with, which has the exact same probabilities as 2d6 vs 7 in every single way.
– Sandra 2020-09-14 21:44 UTC
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Ah, those were the 1d6-1d6 systems, right? A sort of Fate dice alternative. I think they wanted to keep the Fate ladder and that’s why they didn’t want to start using a ladder centred around 7 instead of 0... But I’m just guessing.
– Alex 2020-09-15 08:00 UTC